VCE Stuff > VCE Specialist Mathematics
pi's Specialist Maths Questions
pi:
--- Quote from: moekamo on July 15, 2011, 10:40:18 pm ---no, the relationship you got, -arcsin(x)=arccos(x) (or arcsin(x) + arccos(x)=0) never works, since arcsin(x) + arccos(x) = pi/2 works for any x between -1 and 1 (i.e. any x in the domain of each of these functions), so yes, the constant, + C must be included
and yea i chucked the constants on one side since im a bad-ass
--- End quote ---
Ok, I get it now! Thanks a lot! :)
EDIT: Thanks for the further clarification tony on 2.(i) and luke on 1. :)
luken93:
--- Quote from: Rohitpi on July 15, 2011, 10:41:59 pm ---
--- Quote from: moekamo on July 15, 2011, 10:40:18 pm ---no, the relationship you got, -arcsin(x)=arccos(x) (or arcsin(x) + arccos(x)=0) never works, since arcsin(x) + arccos(x) = pi/2 works for any x between -1 and 1 (i.e. any x in the domain of each of these functions), so yes, the constant, + C must be included
and yea i chucked the constants on one side since im a bad-ass
--- End quote ---
Ok, I get it now! Thanks a lot! :)
EDIT: Thanks for the further clarification tony on 2.(i) and luke on 1. :)
--- End quote ---
hahaha, big help I am!
pi:
OK, more questions/queries!
1. More of a query
If we have , and the answer is , do we need to include the line: x is element of R\{0, -2} in the answer? The textbook seems to, and I wonder if its necessary.
2. More of a query
When do we have to have the modulus in the log when antidifferentiating functions? MQ seems to randomly remove it from some answers (eg. ). Bit confused here... :(
3. Help/query
Is there a proof that is fairly easy to understand for the Gaussian integral ? Even a link would be very helpful and much appreciated.
Thanks :)
(btw, to those who though MQ was easy, try Ex 5E, q4. part e, its a decent question :P )
TrueTears:
3. You won't understand it yet, but the integral is easily computed by converting to polar coordinates and using a double integral. If you want to see the working out: http://en.wikipedia.org/wiki/Gaussian_integral#Careful_proof
i think this thread would be funner with the presence of some nt, combs ; )
pi:
--- Quote from: TrueTears on July 18, 2011, 08:46:15 pm ---3. You won't understand it yet, but the integral is easily computed by converting to polar coordinates and using a double integral. If you want to see the working out: http://en.wikipedia.org/wiki/Gaussian_integral#Careful_proof
--- End quote ---
Hmmm, thought so. Maybe I'll have to pursue this later in life.
--- Quote from: TrueTears on July 18, 2011, 08:46:15 pm ---i think this thread would be funner with the presence of some nt, combs ; )
--- End quote ---
Noooooooooooooooooooooooo! Bad yr11 experience (damn poker!)
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